Understanding the Chebyshev's theorem calculator — concept and principle
This calculator applies Chebyshev's theorem: for any data set or distribution with a finite standard deviation, at least 1 − 1/k² of the values lie within k standard deviations of the mean. Enter k, or the share you want covered, plus the mean and standard deviation, and it gives the guaranteed minimum share, the interval and a comparison with the normal distribution.
How it is calculated
Minimum share within k SD = 1 − 1/k² (for k > 1)
Maximum share outside = 1/k²
Interval = mean ± k × SD
Working backwards: k = 1 ÷ √(1 − share)
- For a normal distribution the share within k SD is erf(k ÷ √2), shown for comparison.
The principle
Chebyshev's inequality comes from a simple counting argument. The variance is the average squared distance from the mean. If more than 1/k² of the values were at least k standard deviations away, those values alone would contribute more than (1/k²) × (kσ)² = σ² to the average squared distance, which is more than the whole variance. So no distribution can have more than 1/k² of its values that far out. The bound works for any shape, which is why it is usually far from tight.
Worked example
Default inputs: k = 2, mean 70, SD 10.
- Minimum share within 2 SD = 1 − 1/2² = 75 %.
- Maximum share outside = 1/4 = 25 %; k used 2.
- Interval = 70 ± 2 × 10 = 50 to 90, width 40.
- For a normal distribution about 95.45 % would lie within 2 SD.
How to read the result
The Chebyshev figure is a guarantee, not an estimate. If you know nothing about the shape of your data, you can still say at least 75 % lie within 2 SD and at least 88.9 % within 3 SD. If the data are roughly bell-shaped, the real share is much higher, closer to the normal comparison. For k ≤ 1 the bound is 0 and tells you nothing.
Common mistakes
- Treating 75 % as the expected share instead of a minimum.
- Using it with k ≤ 1.
- Using the empirical 68–95–99.7 rule for data that are not bell-shaped.
- Confusing the population SD with a rough guess.
Frequently asked questions
What does Chebyshev's theorem say?
At least 1 − 1/k² of any distribution lies within k standard deviations of the mean.
What share is within 3 standard deviations?
At least 88.9 % for any distribution; about 99.7 % for a normal one.
How is it different from the empirical rule?
The empirical rule applies to bell-shaped data; Chebyshev applies to any data but gives weaker bounds.
Sources: Mathematics LibreTexts, Interactive Lecture Notes for Introductory Statistics, §3.4 Interpreting the Mean and Standard Deviation