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Quadratic Inequality Calculator (solve & describe the graph of ax² + bx + c > 0)

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Understanding the quadratic inequality calculator — concept and principle

This calculator solves a quadratic inequality ax² + bx + c > 0 (or <, ≥, ≤) and describes its graph. It gives the solution in interval and inequality notation, the roots, the discriminant, the vertex, which way the parabola opens, and how to draw the boundary and shading for the two-variable version. Use it for algebra homework and graphing practice.

x² − 2x − 8 > 0x² − 2x − 8 > 0−24(1, −9)green: where x² − 2x − 8 > 0Roots−2, 4Vertex(1, −9)OpensupwardSolution(−∞, −2) ∪ (4, ∞)
An upward parabola is above zero outside its roots; open dots mean the roots are excluded.

How it is calculated

  1. Solve ax² + bx + c = 0; the roots split the number line into intervals.
  2. The sign of ax² + bx + c is constant on each interval; check one test point in each.
  3. With b² − 4ac > 0: if a > 0 the expression is positive outside the roots and negative between them; a < 0 reverses this.
  4. With ≥ or ≤, include the roots (square brackets); with > or <, exclude them.

The principle

A quadratic expression can change sign only where it equals zero, at its roots. Between and outside the roots its sign is fixed, so solving the inequality means asking where the parabola lies above or below the x-axis. An upward parabola is below the axis only between its roots, which explains the rule in step 3.

Worked example

Default inputs: x² − 2x − 8 > 0.

  1. Discriminant = (−2)² − 4 × 1 × (−8) = 36; roots x = −2; x = 4.
  2. Vertex at x = 1: y = 1 − 2 − 8 = −9, so (1, −9); the parabola opens upward.
  3. An upward parabola is positive outside its roots: x < −2; x > 4.
  4. Interval notation: (−∞, −2) ∪ (4, ∞); the roots are not included.
  5. Graph of y > x² − 2x − 8: dashed parabola, shading above the parabola.

How to read the result

Test a point to be sure: x = 0 gives −8, not > 0, so 0 is correctly excluded; x = 5 gives 7 > 0, included. The vertex is the lowest point here, at −9, which is why the middle interval is negative.

Common mistakes

Keep in mind: Decimal roots are rounded. For exact interval endpoints, keep roots in surd form, such as 1 ± √3.

Frequently asked questions

How do you solve a quadratic inequality?

Find the roots, then decide on which intervals the parabola is above or below the x-axis.

When is the solution all real numbers?

When the parabola never crosses the x-axis and lies entirely on the required side.

Dashed or solid boundary?

Dashed for < or >, solid for ≤ or ≥.

Sources: OpenStax, College Algebra 2e (2021), §2.7 Linear Inequalities and Absolute Value Inequalities, and §5.1 Quadratic Functions

Checked 9 Nov 2026. OpenStax, Intermediate Algebra 2e (2020), §9.8 Solve Quadratic Inequalities (graphically: where the parabola is above or below the x-axis; algebraically: critical points and test intervals; no x-intercepts when b² − 4ac < 0); OpenStax, College Algebra 2e (2021), §2.7 for interval notation.

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