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Banked Curve Calculator (ideal bank angle)

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Understanding the banked curve calculator — concept and principle

A banked curve is a bend whose surface is tilted toward the inside, like a velodrome or a motor-racing oval. Tilting lets part of the road's normal force point toward the centre, so the car can turn without relying entirely on tyre friction. This calculator gives the ideal bank angle at which a chosen speed needs no friction at all, and, for comparison, the maximum speed on a flat (unbanked) curve with a given friction coefficient.

Car on a road banked at 14.7°On a 300 m curve at 100 km/h, a 14.7° bank lets the road’s push supply the inward force with no friction needed. On a flat road with μ 0.7 the limit is about 163 km/h.A tilted road helps the car turn14.7°road push Nholds up weighttoward centre← curve centretan θ = v² ÷ (r g) = 27.8² ÷ (300 × 9.807)= 0.262 → θ = 14.7° at 100 km/hFlat road, grip μ 0.7 only: max 163 km/h
The tilted road’s push leans inward; its sideways part does the turning.

How it is calculated

The speed is entered in km/h and converted to m/s (V = v ÷ 3.6); r is the curve radius in metres and g = 9.80665 m/s².

The principle

On a frictionless banked surface, only gravity mg and the normal force N act. The vertical part of N, N cos θ, balances the weight, and the horizontal part, N sin θ, provides the centripetal force mV² ÷ r. Dividing one equation by the other cancels both m and N, leaving tan θ = V² ÷ (rg). At this design speed a car could round the bend even on ice. On a flat road, all the centripetal force must come from friction, which is at most μmg; setting μmg = mv² ÷ r gives v_max = √(μgr). Mass cancels in both results.

Worked example

  1. Inputs: v = 100 km/h, r = 300 m, μ = 0.7.
  2. Convert: V = 100 ÷ 3.6 ≈ 27.778 m/s, so V² ≈ 771.60 m²/s².
  3. tan θ = 771.60 ÷ (300 × 9.80665) ≈ 0.26227, so θ ≈ 14.70°.
  4. Flat road: √(0.7 × 9.80665 × 300) = √2,059.40 ≈ 45.381 m/s, × 3.6 ≈ 163.37 km/h.
How Ideal bank angle (°) changes with Speed (km/h)How Ideal bank angle changes with Speed01020304050255075100125150200Example: 14.69611881Speed (km/h)
Each point is the calculator re-run with only “Speed (km/h)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Speed (km/h)Ideal bank angle (°)
250.9391107767
503.751409681
758.392218846
10014.69611881
12522.28387117
15030.54543058
20046.37239167

How to read the result

14.7° is a slope of about 26%, which is typical of a racing oval, not a public road. Public highways usually keep superelevation to a few percent, often capped around 8–12%, and rely on a combination of bank and a small, comfortable amount of side friction (the design relation e + f = v² ÷ (gR) used in highway guidance). For contrast, oval tracks such as Daytona bank their turns at about 31°. The flat-road limit assumes μ = 0.7, roughly a dry road; on a wet road with μ about 0.4 the same curve's limit falls to about 123 km/h, and on ice far lower.

Common mistakes

Keep in mind: These are point-mass, steady-speed estimates. Real road design follows national standards (such as AASHTO in the US or the Korean road structure rules) and must be carried out by qualified engineers.

Frequently asked questions

What happens if I drive slower than the design speed?

The bank provides more inward force than needed, so friction must act up the slope to stop the car sliding down.

What is the maximum speed on a banked curve with friction?

v_max = √(r g (sin θ + μ cos θ) ÷ (cos θ − μ sin θ)), which is larger than both the ideal speed and the flat-road limit.

How do I convert superelevation in percent to degrees?

θ = arctan(e ÷ 100). An 8% superelevation is about 4.57°.

Sources: AASHTO, A Policy on Geometric Design of Highways and Streets (Green Book) · Halliday, Resnick and Walker, Fundamentals of Physics, Wiley

Checked 8 Nov 2026. Standard textbook formulas in SI units, computed in your browser. For learning and estimates — real designs must follow your local codes and be checked by a qualified engineer.

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