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Consolidation Settlement Calculator

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Understanding the consolidation settlement calculator — concept and principle

When a saturated clay layer is loaded by a building, embankment or fill, water is slowly squeezed out of its pores and the ground sinks. This calculator estimates the final primary consolidation settlement of a normally consolidated clay layer and the time needed to reach 90% of that settlement. It is used early in design to judge whether preloading, drains or deep foundations may be needed.

Clay layer under a building settling as water drains outA 4 m clay layer with Cc 0.3 and e₀ 0.9, loaded from 80 to 130 kPa, settles 0.632 × 0.211 = 133 mm; draining both ways, 90% happens in 1.7 years.Loaded clay squeezes out water and sinkssinks133 mmclay H = 4 msandsandCc·H ÷ (1 + e₀)0.3×4÷1.9 = 0.632 mlog of stress ratiolog(130÷80) = 0.211water exits both wayspath H_dr = 2 mSettlement ≈ 133 mm90% done in 1.7 yr (0.848 × 2² ÷ 2)
Water leaves the clay through the sand above and below; the ground sinks 133 mm.

How it is calculated

Cc is the compression index, e₀ the initial void ratio, H the layer thickness (m), σ′₀ the initial effective stress at mid-layer (kPa), Δσ the added stress (kPa) and c_v the coefficient of consolidation (m²/year).

The principle

In a normally consolidated clay, the void ratio falls in a straight line when plotted against the logarithm of effective stress; the slope of that line is Cc. The drop in void ratio is Δe = Cc·log(σ′₁/σ′₀), and because a soil element of height H contains solids of height H/(1 + e₀), the change in height is H·Δe/(1 + e₀). Timing comes from Terzaghi's one-dimensional theory, in which excess pore pressure dissipates like heat diffusing out of a slab; 90% average consolidation corresponds to time factor T_v = 0.848. Because time scales with the square of the drainage path, halving H_dr cuts the time by a factor of four.

Worked example

  1. Inputs: Cc = 0.3, e₀ = 0.9, H = 4 m, σ′₀ = 80 kPa, Δσ = 50 kPa, c_v = 2 m²/year, double drainage.
  2. Cc·H/(1 + e₀) = 0.3 × 4 / 1.9 = 0.6316 m.
  3. log₁₀(130/80) = log₁₀(1.625) = 0.2109.
  4. S = 0.6316 × 0.2109 = 0.1332 m, so final settlement ≈ 133.17 mm.
  5. H_dr = 4/2 = 2 m, so t₉₀ = 0.848 × 2² / 2 = 1.696 years.
How Final settlement (mm) changes with Initial effective stress (kPa)How Final settlement changes with Initia…010020030040020406080100120160Example: 133.1705465Initial effective stress (kPa)
Each point is the calculator re-run with only “Initial effective stress (kPa)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Initial effective stress (kPa)Final settlement (mm)
20343.6219227
40222.4310641
60166.2577483
80133.1705465
100111.215532
12095.53747916
16074.58903921

How to read the result

The settlement is the long-term value after excess pore pressure has fully dissipated; about 90% of it is reached at t₉₀. For structures, differential settlement between supports usually matters more than the total. A result above about 100 mm, as here, usually prompts a look at ground improvement.

Common mistakes

Keep in mind: This is a one-dimensional estimate for a single, normally consolidated layer and ignores immediate and secondary compression. Real foundations must be designed to your local code and checked by a qualified geotechnical engineer.

Frequently asked questions

Where do Cc and e₀ come from?

From an oedometer (one-dimensional consolidation) test on an undisturbed sample.

What is the time to 50% consolidation?

Use T_v = 0.197 instead of 0.848; for the example that gives about 0.39 years.

Does settlement stop after t₉₀?

No. Secondary compression (creep) continues and is estimated with the index Cα.

Sources: K. Terzaghi, Theoretical Soil Mechanics, Wiley, 1943 · B. M. Das, Principles of Geotechnical Engineering, Cengage Learning · ASTM D2435, Standard Test Methods for One-Dimensional Consolidation Properties of Soils Using Incremental Loading

Checked 8 Nov 2026. Standard textbook formulas in SI units, computed in your browser. For learning and estimates — real designs must follow your local codes and be checked by a qualified engineer.

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