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Coriolis Parameter & Geostrophic Wind Calculator

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Understanding the Coriolis parameter and geostrophic wind calculator — concept and principle

Above the friction layer, large-scale wind blows almost parallel to the isobars on a weather map, at a speed set by how tightly the isobars are packed and by the latitude. This calculator finds the Coriolis parameter for a latitude and the geostrophic wind speed for a given pressure difference over a given distance.

Geostrophic balance between pressure force and Coriolis forceAt 37.5° f = 8.88×10⁻⁵ /s; 4 hPa over 300 km with air density 1.2 gives a geostrophic wind of 12.5 m/s.Wind that runs along the isobarsLatitude 37.5°f = 2 × 7.29×10⁻⁵ × sin 37.5°= 8.88 × 10⁻⁵ /shigher pressurelower: −4 hPa300 kmpressure pushCorioliswind 12.5 m/sV = 400 Pa ÷ 300 km ÷ (1.2 × f)= 12.5 m/s ≈ 45 km/h, low pressure on its left
The pressure push and the Coriolis force balance, so the wind blows along the isobars, not across them.

How it is calculated

The principle

On a rotating Earth, moving air is deflected to the right in the Northern Hemisphere and to the left in the Southern. The size of this apparent Coriolis acceleration is f × V, and f depends on the sine of latitude: zero at the equator, largest at the poles. Air starts moving from high to low pressure, gets deflected, and keeps turning until the Coriolis force exactly opposes the pressure-gradient force (1/ρ)·Δp/Δx. In that balance the wind flows along the isobars, with low pressure on the left in the Northern Hemisphere (Buys Ballot's law). Setting the two forces equal and solving for speed gives V_g.

Worked example

  1. Inputs: φ = 37.5°, Δp = 4 hPa, Δx = 300 km, ρ = 1.2 kg/m³.
  2. f = 2 × 7.2921159 × 10⁻⁵ × sin 37.5° = 1.45842 × 10⁻⁴ × 0.60876 = 0.0000887832 s⁻¹.
  3. Pressure gradient: 400 Pa / 300,000 m = 1.3333 × 10⁻³ Pa/m.
  4. V_g = 1.3333 × 10⁻³ / (1.2 × 8.87832 × 10⁻⁵) = 12.51488331 m/s.
  5. In km/h: 12.51488 × 3.6 = 45.0535799 km/h.
How Coriolis parameter f (1/s) changes with Latitude (°)How Coriolis parameter f changes with La…02.5e-055e-057.5e-050.00010.0001250.000159.3818.828.137.546.956.275Example: 0.0000887832Latitude (°)
Each point is the calculator re-run with only “Latitude (°)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Latitude (°)Coriolis parameter f (1/s)
9.380.0000237571
18.80.0000468795
28.10.0000687496
37.50.0000887832
46.90.0001064451
56.20.0001212635
750.0001408729

How to read the result

At mid-latitudes f is about 10⁻⁴ s⁻¹ (1.03 × 10⁻⁴ at 45°). Tighter isobars or a lower latitude give faster geostrophic wind for the same pressure difference. Charts commonly draw isobars every 4 hPa, so the distance between neighbouring lines tells you the wind speed at a glance. Actual surface winds are typically weaker than V_g and cross the isobars toward low pressure because of friction; at upper levels V_g is usually a good estimate.

Common mistakes

Keep in mind: Geostrophic balance ignores friction, curvature of the flow and acceleration. It works best for large, slowly changing systems away from the equator and is not a forecast of the wind you will feel at ground level.

Frequently asked questions

Why does the Coriolis force vanish at the equator?

Only the component of Earth's rotation around the local vertical deflects horizontal winds, and that component is Ω sin φ, which is zero at φ = 0.

Why do winds blow around lows instead of into them?

Over large scales the Coriolis force turns the flow until it balances the pressure gradient, so air circulates along the isobars. Friction near the ground lets some air spiral inward.

Sources: J. R. Holton and G. J. Hakim, An Introduction to Dynamic Meteorology, Academic Press · J. M. Wallace and P. V. Hobbs, Atmospheric Science: An Introductory Survey, Academic Press

Checked 8 Nov 2026. Standard textbook formulas in SI units, computed in your browser. For learning and estimates — real designs must follow your local codes and be checked by a qualified engineer.

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