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Foehn Wind Temperature Calculator

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Understanding the foehn wind temperature calculator — concept and principle

A foehn is a warm, dry wind that descends the lee side of a mountain range. This calculator follows a parcel up and over a mountain to estimate the cloud base, the summit temperature and the temperature after it descends.

Foehn wind over a 2,000 m mountainAir at 15 °C cools dry to 8.9 °C at the 625 m cloud base, then moist to 0.6 °C at the summit, and warms dry to 20.2 °C on the lee side.Foehn: wet up, dry downsummit 0.6 °Ccloud base 625 m · 8.9 °C−9.8 °C/kmin cloud −6 °C/kmdry +9.8 °C/km15 °Cwindward base20.2 °Clee base→Rain falls out, so the air comes down 5.2 °C warmer
Cooling slowly in cloud but warming fast on the way down leaves the lee side 5.2 °C warmer.

How it is calculated

  1. Cloud base (lifting condensation level): h_c ≈ 125 m × (T − T_d), capped at the mountain height H.
  2. Up to cloud base: the parcel cools at the dry adiabatic rate of 9.8 °C per km.
  3. From cloud base to summit: it cools at a moist rate of about 6 °C per km, because condensation releases latent heat. Summit temperature: T_s = T − 0.0098 × h_c − 0.006 × (H − h_c).
  4. Down the lee side: assuming the cloud water has rained out, the parcel warms at the dry rate all the way down: T_lee = T_s + 0.0098 × H.

Temperatures are in °C and heights in metres above the windward base.

The principle

Rising air expands and cools; sinking air is compressed and warms. Without condensation this happens at the dry adiabatic lapse rate, g/c_p ≈ 9.8 °C/km. The dew point falls much more slowly with height, so the gap between temperature and dew point closes by about 8 °C per km, which is where the 125 m per degree rule comes from. Once saturated, condensing water vapour releases heat, so the cooling slows. If the condensed water falls as rain or snow on the windward slope, the descending air has nothing left to evaporate and warms at the full dry rate. It ends warmer than it started, by the latent heat released by the water that fell out.

Worked example

  1. Inputs: T = 15 °C, T_d = 10 °C, H = 2000 m.
  2. Cloud base: 125 × (15 − 10) = 625 m.
  3. Dry cooling to 625 m: 0.0098 × 625 = 6.125 °C. Moist cooling over 1,375 m: 0.006 × 1375 = 8.25 °C.
  4. Summit: 15 − 6.125 − 8.25 = 0.625 °C.
  5. Lee base: 0.625 + 0.0098 × 2000 = 0.625 + 19.6 = 20.225 °C, a gain of about 5.2 °C.
How Cloud base on windward side (m) changes with Windward temperature at base (°C)How Cloud base on windward side changes…-1,00001,0002,0003.757.511.21518.822.530Example: 625Windward temperature at base (°C)
Each point is the calculator re-run with only “Windward temperature at base (°C)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Windward temperature at base (°C)Cloud base on windward side (m)
3.75-781.25
7.5-312.5
11.2156.25
15625
18.81,093.75
22.51,562.5
302,000

How to read the result

The larger the part of the climb that is saturated, the bigger the warming on the lee side. If the cloud base is at or above the summit, no condensation occurs and the leeward temperature equals the windward one. Warming of a few degrees with a sharp drop in humidity is typical and raises wildfire risk downwind. Korea's nopsae, a late-spring northeasterly crossing the Taebaek Mountains into the Yeongseo region, is a classic example.

Common mistakes

Keep in mind: This is an idealised parcel model. Real foehn events also involve air descending from higher levels without rising first, mixing and turbulence, so measured temperatures can differ noticeably.

Frequently asked questions

Why is foehn air so dry?

Its water vapour condensed and fell out on the windward side, and the air warmed on descent, so relative humidity drops sharply.

Where does the 125 m per °C rule come from?

The temperature falls by 9.8 °C/km and the dew point by roughly 1.8 to 2 °C/km, so their gap shrinks by about 8 °C/km.

Sources: J. M. Wallace and P. V. Hobbs, Atmospheric Science: An Introductory Survey, Academic Press · C. D. Ahrens and R. Henson, Meteorology Today, Cengage Learning

Checked 8 Nov 2026. Standard textbook formulas in SI units, computed in your browser. For learning and estimates — real designs must follow your local codes and be checked by a qualified engineer.

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