Understanding the Hooke's law and spring calculator — concept and principle
Hooke's law describes how an ideal spring pushes back in proportion to how far it is stretched or compressed. This calculator gives the spring force, the elastic energy stored, and the period and frequency with which an attached mass would bounce. It is used for physics labs, choosing springs for mechanisms, suspension and vibration estimates, and spring scales.
How it is calculated
- Force: F = k x, where k is the spring constant in N/m and x the extension or compression in metres from the natural length.
- Stored energy: E = ½ k x², in joules.
- Period: T = 2π √(m ÷ k), in seconds, for a mass m (kg) on the spring.
- Frequency: f = (1 ÷ 2π) √(k ÷ m) = 1 ÷ T, in hertz.
The principle
For small deformations, the atomic bonds in a material behave like tiny springs, so the restoring force is proportional to displacement; Robert Hooke summed this up in 1678 as "ut tensio, sic vis" (as the extension, so the force). The stored energy is the area under the force–extension line, a triangle with height kx and base x, hence ½kx². A mass on such a spring feels a force that always points back to equilibrium and grows with distance, which produces simple harmonic motion. A stiffer spring pulls back harder and speeds the motion up; a larger mass has more inertia and slows it down, which is why T depends on √(m ÷ k) and not on the amplitude.
Worked example
- Inputs: k = 200 N/m, x = 0.05 m, m = 0.5 kg.
- Force: 200 × 0.05 = 10 N.
- Energy: ½ × 200 × 0.05² = 0.25 J.
- Period: 2π × √(0.5 ÷ 200) = 2π × 0.05 ≈ 0.31416 s.
- Frequency: 1 ÷ 0.31416 ≈ 3.1831 Hz.
| Spring constant k (N/m) | Force (N) |
|---|---|
| 50 | 2.5 |
| 100 | 5 |
| 150 | 7.5 |
| 200 | 10 |
| 250 | 12.5 |
| 300 | 15 |
| 400 | 20 |
How to read the result
A k of 200 N/m means each centimetre of stretch adds 2 N. The period does not change with how far you pull the mass, as long as the spring stays in its linear range. If you hang the mass vertically, it simply sits lower by mg ÷ k (here about 2.45 cm) and oscillates about that point with the same period. To halve the period, you need four times the stiffness or a quarter of the mass.
Common mistakes
- Entering x in centimetres or millimetres instead of metres.
- Measuring x from the hanging position instead of the natural length when computing force.
- Ignoring the spring's own mass, which lengthens the period slightly.
- Assuming Hooke's law holds far beyond the elastic limit.
Frequently asked questions
What units does the spring constant have?
Newtons per metre (N/m). Catalogues often use N/mm; 1 N/mm = 1,000 N/m.
How do I measure k?
Hang a known mass, measure the extension, and divide the weight mg by that extension.
Does gravity change the period of a vertical spring?
No. Gravity shifts the equilibrium position, but the period is still 2π√(m ÷ k).
Sources: Robert Hooke, Lectures de Potentia Restitutiva, or of Spring, London, 1678 · Halliday, Resnick and Walker, Fundamentals of Physics, Wiley