Understanding the insertion loss calculator — concept and principle
This calculator finds the insertion loss of a cable, filter, connector, attenuator or other component, in decibels, from readings of power or voltage at the load with and without the device in place. It also shows the share of power that gets through. RF technicians, audio engineers and fibre-optic installers use it daily.
How it is calculated
Power readings: IL = 10 log₁₀(P_without ÷ P_with) dB
Voltage readings across the same load: IL = 20 log₁₀(V_without ÷ V_with) dB
Power reaching the load = P_with ÷ P_without × 100%
- Both readings must use the same unit. A positive IL is a loss; a negative value means a gain.
The principle
Decibels express ratios on a logarithmic scale, so losses in a chain simply add. Power ratios use 10 log₁₀. Power across a fixed resistance is proportional to the voltage squared, so the same ratio expressed in voltages uses 20 log₁₀. Insertion loss compares the power delivered to the load with and without the device, using the same source and load, so it includes both the energy the device absorbs and the energy it reflects back towards the source.
Worked example
Default inputs: power readings, 10 mW without the device, 8 mW with it.
- Ratio = 8 ÷ 10 = 0.8, so 80% of the power reaches the load and 20% is lost.
- IL = 10 × log₁₀(10 ÷ 8) = 0.969 dB.
- Equivalent voltage ratio = √0.8 = 0.8944.
- The value is positive, so it causes a loss.
| With the device inserted: power (mW) or voltage (V) | Insertion loss (dB) |
|---|---|
| 2 | 6.99 |
| 4 | 3.979 |
| 6 | 2.218 |
| 8 | 0.969 |
| 10 | 0 |
| 12 | -0.792 |
| 16 | -2.041 |
How to read the result
3 dB means about half the power gets through and 10 dB means a tenth. A good connector typically loses only a fraction of a decibel, while a long cable at high frequency can lose many decibels. Add the dB figures of components in series to get the total loss.
Common mistakes
- Using 20 log for power readings or 10 log for voltages.
- Measuring with different source or load conditions in the two readings.
- Mixing W and mW between the two readings.
- Confusing insertion loss with return loss, which measures reflection.
Frequently asked questions
What does 1 dB of loss mean?
About 79% of the power gets through.
Can insertion loss be negative?
Yes, if the device amplifies, as with an active filter or amplifier.
How do I find the total loss of several parts?
Add their insertion losses in dB.
Sources: Standard definitions of the decibel (10 log₁₀ for power, 20 log₁₀ for voltage across equal resistances) and of insertion loss