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Liquid Leak Rate Through a Hole Calculator

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Understanding the liquid leak rate calculator — concept and principle

When a tank or pipe develops a hole, hazard assessment first asks how fast the liquid escapes. This calculator uses the classic orifice equation to estimate the initial leak rate through a round hole from vessel pressure, liquid head and density, for spill scenarios and containment sizing.

Liquid leak through a 10 mm hole5 bar plus 2 m of water gives 519,620 Pa; a 10 mm hole with C_d 0.61 leaks 1.54 kg/s, 92.7 litres a minute.Pressure + liquid height push it out5 bar2 mholeØ 10 mmhole sizeC_d 0.61sharp edgeΔp = 500,000 + 1000 × 9.81 × 2 = 519,620 Paṁ = 0.61 × 7.854×10⁻⁵ m² × √(2 × 1000 × 519,620)1.54 kg/s = 92.7 L/mina 10 L bucket fills in about 6.5 s
Both the gauge pressure and the liquid head above the hole drive the jet.

How it is calculated

ṁ = C_d · A · √(2ρ · (Δp + ρgh))

The principle

Bernoulli's equation says that pressure energy turns into kinetic energy as liquid accelerates through the hole: ½ρv² = Δp_total, so the ideal velocity is v = √(2Δp_total / ρ). Multiplying by area and density gives a mass flow. Real jets contract just past a sharp edge (the vena contracta) and lose a little energy to friction, so the real flow is smaller; C_d lumps both effects into one factor. Because flow depends on the square root of pressure, quadrupling the pressure only doubles the leak, while doubling the hole diameter quadruples it.

Worked example

  1. Inputs: d = 10 mm, Δp = 5 bar, h = 2 m, ρ = 1000 kg/m³, C_d = 0.61.
  2. A = π × 0.01² / 4 = 7.854 × 10⁻⁵ m².
  3. Total driving pressure: 500,000 + 1000 × 9.81 × 2 = 519,620 Pa.
  4. √(2 × 1000 × 519,620) = 32,237.2 kg/(m²·s).
  5. ṁ = 0.61 × 7.854 × 10⁻⁵ × 32,237.2 = 1.5445 kg/s.
  6. Volume rate: 1.5445 / 1000 × 60,000 = 92.668 L/min.
How Leak rate (kg/s) changes with Hole diameter (mm)How Leak rate changes with Hole diameter024682.557.51012.51520Example: 1.54446348Hole diameter (mm)
Each point is the calculator re-run with only “Hole diameter (mm)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Hole diameter (mm)Leak rate (kg/s)
2.50.0965289675
50.38611587
7.50.8687607074
101.54446348
12.52.413224187
153.47504283
206.177853919

How to read the result

The value is the initial rate. As the vessel drains and pressure or head falls, the rate drops, so total release time is longer than inventory divided by the initial rate. Hole size dominates: a 20 mm hole leaks four times as much as a 10 mm one. For worst-case screening a C_d of 1 is sometimes used for conservatism; 0.61 represents a sharp-edged hole and rounded or short-pipe openings give higher values.

Common mistakes

Keep in mind: This is an educational estimate for incompressible, non-flashing liquid with constant pressure. Process safety studies and consequence modelling must follow applicable codes and be reviewed by qualified engineers.

Frequently asked questions

How long will the tank take to empty?

For an unpressurised open tank the head falls as it drains, so the rate is not constant; integrating gives a drain time about twice the time computed at the initial rate.

Can I use it for gas leaks?

No. Gases are compressible and often reach choked flow, which needs a different equation.

What C_d should I use?

About 0.6 for sharp-edged holes; values closer to 1 for well-rounded nozzles; 1 if you want a conservative upper bound.

Sources: D. A. Crowl and J. F. Louvar, Chemical Process Safety: Fundamentals with Applications, Prentice Hall · Perry's Chemical Engineers' Handbook, McGraw-Hill (flow through orifices)

Checked 8 Nov 2026. Standard textbook formulas in SI units, computed in your browser. For learning and estimates — real designs must follow your local codes and be checked by a qualified engineer.

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