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Power Factor Correction Capacitor Calculator

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Understanding the power factor correction calculator — concept and principle

This calculator sizes the capacitor bank needed to raise a load's power factor from its present value to a target, in kvar, and converts that into the capacitance per phase for a delta-connected three-phase bank. Factories and commercial buildings use power factor correction to avoid utility penalties, free up transformer and cable capacity, and reduce losses.

Power factor correction shrinks the power triangleA 50 kW load at PF 0.75 draws 44.1 kvar; a 27.66 kvar capacitor bank leaves 16.4 kvar, PF 0.95, cutting apparent power from 66.7 to 52.6 kVA.A capacitor cancels part of Q44.1 kvar16.4kvarP = 50 kW stays the sameQc27.66kvar183.4 µFper phasePF 0.75 before: 66.7 kVA · 96.2 APF 0.95 after: 52.6 kVA · 76.0 A
Same 50 kW of work, but a smaller triangle: less current in the cables.

How it is calculated

The principle

An inductive load draws reactive power Q = P · tan φ. A capacitor draws reactive power of the opposite sign, so placing it in parallel with the load cancels part of the inductive kvar locally. The real power P does not change; only the reactive part supplied by the network shrinks, from P tan φ₁ to P tan φ₂. The difference is exactly the capacitor rating. In a delta bank, each of the three capacitors sits across the full line voltage and supplies one third of Q_c, and a capacitor's reactive power is V² · 2πfC, which rearranges to the capacitance formula above.

Worked example

  1. Inputs: P = 50 kW, present PF 0.75, target PF 0.95, 400 V, 50 Hz.
  2. tan(arccos 0.75) = 0.88192; tan(arccos 0.95) = 0.32868.
  3. Q_c = 50 × (0.88192 − 0.32868) = 27.662 kvar.
  4. Per phase: 27,661.6 ÷ (3 × 2π × 50 × 400²) = 1.8344 × 10⁻⁴ F = 183.44 µF.
  5. Effect: apparent power falls from 50/0.75 = 66.7 kVA to 50/0.95 = 52.6 kVA, and line current at 400 V falls from about 96.2 A to 76.0 A.
How Capacitor (kvar) changes with Real power (kW)How Capacitor changes with Real power010203040506012.52537.55062.575100Example: 27.66164993Real power (kW)
Each point is the calculator re-run with only “Real power (kW)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Real power (kW)Capacitor (kvar)
12.56.915412481
2513.83082496
37.520.74623744
5027.66164993
62.534.57706241
7541.49247489
10055.32329985

How to read the result

Choose the nearest standard capacitor or bank step at or slightly above the computed kvar, at a voltage rating suited to the system. Targets of 0.95 to 0.98 are common; pushing to exactly 1.0 gives little extra benefit and risks overcorrection to a leading power factor when the load drops.

Common mistakes

Keep in mind: Harmonics from drives and rectifiers can resonate with correction capacitors and overheat them; detuned reactors may be needed. Capacitor banks require proper protection, discharge resistors and installation under local electrical codes by a qualified electrician.

Frequently asked questions

Does correcting power factor lower my energy bill?

It reduces reactive-power charges and cable losses where the tariff includes them. The real energy (kWh) used by the load stays the same.

Where should the capacitors be installed?

At the main switchboard for central correction or at large motors for individual correction. Local correction also relieves the feeder cables.

What is the formula for a single-phase load?

The kvar formula is the same; the capacitance is C = Q_c / (2πf · V²).

Sources: IEC 60831-1, Shunt power capacitors of the self-healing type for AC systems having a rated voltage up to and including 1000 V · IEEE Std 1036, IEEE Guide for the Application of Shunt Power Capacitors

Checked 8 Nov 2026. Standard textbook formulas in SI units, computed in your browser. For learning and estimates — real designs must follow your local codes and be checked by a qualified engineer.

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