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Raoult’s Law Calculator (vapor pressure of a solution with a nonvolatile solute)

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Understanding the Raoult's law calculator — concept and principle

This calculator applies Raoult's law to find the vapour pressure of a solution containing a nonvolatile solute, the vapour-pressure lowering and the mole fractions. It accounts for electrolytes through the van 't Hoff factor. It is used in general and physical chemistry for colligative properties.

Raoult's lawSugar lowers vapour pressureGlucose100 gWater500 gP*23.76 mmHgX = 27.75 ÷ 28.31 = 0.9804P = 0.9804 × 23.76Vapour pressure23.29 mmHgLowering0.4659 mmHgRelative lowering1.96 %
Only water molecules evaporate, so the vapour pressure falls in step with water’s mole fraction.

How it is calculated

n_solvent = solvent mass ÷ molar mass; n_particles = (solute mass ÷ molar mass) × i

X_solvent = n_solvent ÷ (n_solvent + n_particles)

P_solution = X_solvent × P*; ΔP = P* − P_solution = X_solute × P*

The principle

Molecules escape from a liquid's surface into the vapour. Dissolving a nonvolatile solute means some of the surface is occupied by solute particles that do not evaporate, so fewer solvent molecules escape per second. In an ideal solution the vapour pressure falls in direct proportion to the solvent's mole fraction. The lowering depends only on how many particles are dissolved, not what they are, which makes it a colligative property like boiling-point elevation.

Worked example

Default inputs: 100 g glucose (180.16 g/mol), i = 1, 500 g water (18.015 g/mol), P* = 23.76 (mmHg, water at 25 °C).

  1. Solute particles = 100 ÷ 180.16 = 0.5551 mol; solvent = 500 ÷ 18.015 = 27.75 mol.
  2. X_solvent = 27.75 ÷ 28.31 = 0.9804; X_solute = 0.0196.
  3. P = 0.9804 × 23.76 = 23.29.
  4. Lowering ΔP = 0.4659, a relative lowering of 1.96%.
How Vapor pressure of the solution (unit of P*) changes with Vapor pressure of the pure solvent P* (any unit)How Vapor pressure of the solution chang…010203040505.9411.917.823.829.735.647.5Example: 23.29Vapor pressure of the pure solvent P* (any unit)
Each point is the calculator re-run with only “Vapor pressure of the pure solvent P* (any unit)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Vapor pressure of the pure solvent P* (any unit)Vapor pressure of the solution (unit of P*)
5.945.824
11.911.65
17.817.47
23.823.29
29.729.12
35.634.94
47.546.59

How to read the result

The relative lowering equals the solute particle mole fraction. Doubling the solute roughly doubles the lowering in dilute solutions. Salts split into ions, so the same moles of NaCl lower the vapour pressure about twice as much as glucose.

Common mistakes

Keep in mind: Raoult's law describes ideal solutions. Concentrated or strongly interacting solutions deviate.

Frequently asked questions

Why does a solute lower vapour pressure?

Fewer solvent molecules are at the surface to escape.

Is the lowering the same for all solutes?

For ideal dilute solutions it depends only on the number of dissolved particles.

What unit is the result in?

The same unit you entered for P*.

How is this related to boiling-point elevation?

Lower vapour pressure means the solution must be heated more to reach atmospheric pressure.

Sources: OpenStax, Chemistry: Atoms First 2e, section 11.4 "Colligative Properties"

Checked 9 Nov 2026. OpenStax, Chemistry: Atoms First 2e, §11.4 “Colligative Properties” (mole fraction, Raoult’s law PA = XAP*A, vapor pressure lowering, van ’t Hoff factor).

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