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Tension Calculator (load hung from two ropes, or a rope accelerating up/down)

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Understanding the rope tension calculator — concept and principle

This calculator finds the tension in ropes, cables or chains that hold a load. In the first mode a weight hangs from two ropes at different angles, as with a sign or a lifting sling. In the second mode one rope lifts or lowers a load that is accelerating. It is a standard physics problem and a useful check before rigging.

Tension in two ropesA 20 kg load on two ropes30°45°20 kg196.1 NT₁ 143.6 NT₂ 175.8 NHorizontal pulls cancel: 124.3 N eachThe steeper rope carries more.
Rope 2 is steeper (45°), so it carries 175.8 N against 143.6 N in rope 1.

How it is calculated

Two ropes:

T₁ = m g cos θ₂ ÷ sin(θ₁ + θ₂)

T₂ = m g cos θ₁ ÷ sin(θ₁ + θ₂)

Horizontal pull = T₁ cos θ₁ = T₂ cos θ₂

Single rope: T = m (g + a), with a positive upward

The principle

A load that is not accelerating is in equilibrium: all forces on it add up to zero. Split each rope's pull into horizontal and vertical parts. The horizontal parts must cancel, so the two ropes pull sideways equally hard. The vertical parts must add up to the weight. Two equations with two unknowns give the formulas above. The steeper rope carries more of the load. As both ropes get flatter, their vertical parts shrink and the tensions grow without limit, which is why a rope can never be pulled perfectly straight under a load. With one vertical rope, Newton's second law gives T − mg = ma.

Worked example

Default inputs: two ropes, mass 20 kg, θ₁ = 30°, θ₂ = 45°.

  1. Weight = 20 × 9.80665 = 196.1 N.
  2. sin(30° + 45°) = sin 75° = 0.9659.
  3. T₁ = 196.13 × cos 45° ÷ 0.9659 = 196.13 × 0.7071 ÷ 0.9659 = 143.6 N (14.64 kgf).
  4. T₂ = 196.13 × cos 30° ÷ 0.9659 = 196.13 × 0.8660 ÷ 0.9659 = 175.8 N (17.93 kgf).
  5. Horizontal pull = 143.6 × cos 30° = 124.3 N, the same for both ropes.
How Tension in rope 1 (N) changes with Rope 2 angle above the horizontal (°)How Tension in rope 1 changes with Rope…010020030011.222.533.84556.267.590Example: 143.6Rope 2 angle above the horizontal (°)
Each point is the calculator re-run with only “Rope 2 angle above the horizontal (°)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Rope 2 angle above the horizontal (°)Tension in rope 1 (N)
11.2291.8
22.5228.4
33.8181.8
45143.6
56.2109.2
67.575.7
900

How to read the result

Compare each tension with the working load limit of the rope, sling or hardware, not its breaking strength. Rigging practice often avoids very shallow sling angles because tensions rise sharply as angles approach horizontal. In the accelerating case, a rope lifting a load upward with acceleration carries more than its weight; one lowering it while speeding up carries less.

Common mistakes

Keep in mind: Ropes are assumed massless and loads static or smoothly accelerating. Real lifting must follow rated working load limits, local regulations and a competent person's rigging plan.

Frequently asked questions

Why is tension higher with flatter ropes?

A flatter rope has a smaller vertical component, so it must pull harder to support the same weight.

What happens if both angles are 90°?

Both ropes hang straight down and each carries half the weight.

How does acceleration change the tension?

Accelerating upward adds m × a to the weight; accelerating downward subtracts it.

Is kgf an official unit?

It is not an SI unit, but it is still used to compare with load ratings given in kilograms.

Sources: Static equilibrium ΣF = 0 and Newton's second law ΣF = ma (standard mechanics); standard gravity 9.80665 m/s² (CGPM)

Checked 9 Nov 2026. Static equilibrium ΣF = 0 resolved into horizontal and vertical components, and Newton’s second law ΣF = ma for the accelerating case (standard mechanics); standard gravity 9.80665 m/s².

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