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Torsion Spring Calculator (torque, spring rate & bending stress)

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Understanding the torsion spring calculator — concept and principle

A torsion spring is a coiled wire that resists twisting, as in clothes pegs, mousetraps, hinges and garage doors. This calculator estimates the spring rate, the torque at a given angle and the bending stress in the wire from the wire diameter, mean coil diameter, number of active coils and the wire's Young's modulus.

Torsion spring torque and stressTwisting a 6-coil spring by 90°90°wire 2 mm · coil 20 mm2,469 N·mm / turn617.3 N·mmstress 849.3 MPak′ = d⁴E ÷ (10.8 D N) · Ki 1.081
A quarter turn of this spring needs 617.3 N·mm and stresses the wire to 849 MPa.

How it is calculated

Design rate per turn: k′ = d⁴ × E ÷ (10.8 × D × N)

Torque at angle θ: M = k′ × θ ÷ 360°

Ideal rate per radian: d⁴ × E ÷ (64 × D × N)

Spring index C = D ÷ d; Ki = (4C² − C − 1) ÷ (4C(C − 1))

Bending stress σ = Ki × 32M ÷ (π d³)

The principle

Twisting a torsion spring actually bends its wire around the coil, so the wire behaves like a long curved beam loaded in bending. Beam theory gives the ideal angle θ = 64MDN ÷ (d⁴E), so stiffness rises with the fourth power of wire diameter and falls with coil diameter and number of turns. Friction between coils and against the arbor makes real springs slightly softer, so Shigley's design equation uses 10.8 per turn instead of the ideal 64 ÷ 2π ≈ 10.2. Bending stress is highest on the inside of the coil, where the curved wire concentrates stress; Ki corrects for this.

Worked example

Default inputs: d = 2 mm, D = 20 mm, N = 6, E = 200 GPa, angle 90°.

  1. E = 200,000 N/mm²; d⁴ = 16 mm⁴.
  2. k′ = 16 × 200,000 ÷ (10.8 × 20 × 6) = 3,200,000 ÷ 1,296 = 2,469 N·mm per turn (= 6.859 N·mm per degree).
  3. M = 2,469 × 90 ÷ 360 = 617.3 N·mm = 0.6173 N·m.
  4. Ideal rate = 3,200,000 ÷ (64 × 120) = 416.7 N·mm per rad.
  5. C = 20 ÷ 2 = 10; Ki = (400 − 10 − 1) ÷ 360 = 1.081.
  6. σ = 1.081 × 32 × 617.3 ÷ (π × 8) = 849.3 MPa.
How Torque at this angle (N·mm) changes with Wire diameter d (mm)How Torque at this angle changes with Wi…02,0004,0006,0008,00010,0000.511.522.534Example: 617.3Wire diameter d (mm)
Each point is the calculator re-run with only “Wire diameter d (mm)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Wire diameter d (mm)Torque at this angle (N·mm)
0.52.411
138.58
1.5195.3
2617.3
2.51,507
33,125
49,877

How to read the result

Compare the stress with the allowable bending stress for your wire grade and size from a spring-wire standard or supplier; high-strength music wire allows much more than ordinary steel. Spring index between about 4 and 12 is generally easy to manufacture. When the spring winds up, its coil diameter shrinks, so leave clearance around the arbor.

Common mistakes

Keep in mind: Results are estimates for the coil body only. Fatigue, leg bending and manufacturer tolerances matter in real designs, so confirm with the spring maker's data and testing.

Frequently asked questions

Why does wire diameter matter so much?

Stiffness depends on d⁴, so a 10 % thicker wire is about 46 % stiffer.

What is a typical Young's modulus for spring steel?

Around 200 GPa for carbon steel music wire.

Should a torsion spring wind tighter or looser under load?

It is normally loaded so that it winds tighter, which reduces stress.

Sources: Shigley & Mischke, Mechanical Engineering Design, torsion spring equations (Ki, stress, deflection and design rate k′ = d⁴E/(10.8DN)) · University of Idaho, Machine Design "Springs" poster (S. Scott, V. Schiweck, N. Cropper)

Checked 9 Nov 2026. University of Idaho, Machine Design “Springs” poster (S. Scott, V. Schiweck, N. Cropper), with equations from Shigley & Mischke, Mechanical Engineering Design: Ki = (4C² − C − 1)/(4C(C − 1)) (eq. 10-32), σ = Ki·32Fr/(πd³) (eq. 10-33), θ = 64FrDN/(d⁴E) (eq. 10-34) and k′ = d⁴E/(10.8DN) (eq. 10-37).

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