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Water Heating Time & Cost Calculator

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Understanding the water heating time and cost calculator — concept and principle

How long will a kettle, immersion heater or water boiler take to heat a given amount of water, and how much electricity will it use? This calculator answers both from the water volume, the start and target temperatures, the heater's power and its efficiency. Multiply the energy by your electricity price to get the cost.

Time to heat 1.5 L of water with a 2,000 W kettleHeating 1.5 L from 15 to 100 °C needs 1.5 × 4,186 × 85 = 533,715 J. At 90% efficiency 1,800 of the 2,000 W reaches the water, so it takes 296.5 s, about 4.94 minutes, and draws 0.165 kWh.Heat needed ÷ useful power = time1.5 L water, 15 → 100 °CQ = 1.5 × 4,186 × 85= 533.7 kJHeater 2,000 W at 90% efficiency1,800 W into the water200200 W lost to air533,715 J ÷ 1,800 W = 296.5 s≈ 4.94 min · uses 0.165 kWh
533.7 kJ of heat at 1,800 useful watts takes about 4.94 minutes.

How it is calculated

The principle

The water needs a fixed amount of heat, set by its mass, its specific heat and the temperature rise (Q = mcΔT). An electric heater turns electrical power into heat at a steady rate, but not all of it reaches the water: some warms the kettle body, escapes from the surface or is lost to the air. Efficiency η captures that share. Dividing the required heat by the useful heating rate P × η gives the time; dividing it by η alone gives the electricity actually drawn from the socket.

Worked example

  1. Inputs: V = 1.5 L, T₁ = 15 °C, T₂ = 100 °C, P = 2000 W, η = 90%.
  2. Q = 1.5 × 4186 × (100 − 15) = 1.5 × 4186 × 85 = 533,715 J.
  3. Useful power = 2000 × 0.90 = 1800 W.
  4. Time = 533,715 ÷ 1800 = 296.5 s = 4.941805556 min (about 4 min 57 s).
  5. Energy = 533,715 ÷ 0.90 ÷ 3,600,000 = 0.1647268519 kWh.
How Time (min) changes with Heater power (W)How Time changes with Heater power051015205001,0001,5002,0002,5003,0004,000Example: 4.941805556Heater power (W)
Each point is the calculator re-run with only “Heater power (W)” changed; the gold point is the default example. Change the inputs above and this chart follows your numbers.
Heater power (W)Time (min)
50019.76722222
1,0009.883611111
1,5006.589074074
2,0004.941805556
2,5003.953444444
3,0003.294537037
4,0002.470902778

How to read the result

Cost is the energy times your tariff, so at a price p per kWh this boil costs about 0.165 × p. Time scales directly with volume and temperature rise and inversely with power: half the water takes half the time, and a 3 kW kettle is a third faster than a 2 kW one. Electric kettles typically have high efficiency because the element sits in the water; stovetop and open pans lose much more. The energy figure does not depend on power, only on efficiency.

Common mistakes

Keep in mind: The model assumes constant power and efficiency and ignores heat lost while the water is already hot, so long heating times or uninsulated tanks will take longer than shown. This is an estimate, not a measurement.

Frequently asked questions

Is it cheaper to boil water in a kettle or on a gas stove?

It depends on local electricity and gas prices and on the burner's efficiency; compare price per kWh of each fuel divided by its efficiency.

Does a fuller kettle boil less efficiently?

Roughly the same per litre; very small amounts are less efficient because the kettle itself still has to be heated.

Why does water take longer to heat at the start of winter?

The tap water starts colder, so the temperature rise T₂ − T₁ is larger.

Sources: D. Halliday, R. Resnick and J. Walker, Fundamentals of Physics, Wiley, chapter on temperature, heat and the first law

Checked 8 Nov 2026. Standard textbook formulas in SI units, computed in your browser. For learning and estimates — real designs must follow your local codes and be checked by a qualified engineer.

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