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Cycling Breakaway Calculator (will the peloton catch the break?)

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Understanding the cycling breakaway calculator — concept and principle

Will the peloton catch the breakaway before the finish? This calculator answers that with simple kinematics from the time gap, the speeds of the breakaway and the chasing group, and the distance left. It tells you where the catch happens, how many seconds the chase gains per 10 km and how fast the chase must ride to catch the break exactly on the line.

Breakaway catch2-minute gap, 35 km to goGap120 sBreak · chase42 · 46 km/hTo go35 kmchase gains 7.45 s per kmCaught?Yes, at 16.1 kmBreak needs43.8 km/hConstant speeds; real races vary
Gaining 74.5 s per 10 km, the chase closes 120 s after 16.1 km.

How it is calculated

Breakaway finish time = D ÷ vb

Gap at the finish = g + D ÷ vc − D ÷ vb (caught if ≤ 0 and vc > vb)

Seconds gained per km = 3,600 × (1/vb − 1/vc)

Catch point = vb × vc × g ÷ (vc − vb) (km, with g in hours)

Chase speed to catch on the line = D ÷ (D ÷ vb − g)

The principle

A time gap of g seconds means the chasers pass any point g seconds after the breakaway. If both groups hold steady speeds, the chasers need less time per kilometre, so the gap shrinks by a fixed number of seconds per kilometre. The catch occurs when the time saved equals the original gap. Measured from where the breakaway is now, the chase is effectively vb × g kilometres behind and closes at vc − vb, which gives the catch point formula. If the catch point is beyond the finish, the breakaway survives.

Worked example

Default inputs: gap 120 s, breakaway 42 km/h, chase 46 km/h, 35 km left.

  1. Breakaway finish time = 35 ÷ 42 h = 0:50:00.
  2. Chase time to the finish = 120 s + 35 ÷ 46 h = 120 + 2,739 s; gap at the line = 2,859 − 3,000 = −141 s, so caught: yes (gap at the finish —).
  3. Gain per km = 3,600 × (1/42 − 1/46) = 7.45 s, so 74.5 s per 10 km.
  4. Catch point = 42 × 46 × (120 ÷ 3,600) ÷ 4 = 16.1 km from here.
  5. Speed needed to catch exactly at the line = 35 ÷ (0.8333 − 0.0333) = 43.8 km/h.

How to read the result

The classic rule of thumb that a peloton gains about a minute per 10 km is consistent with a few km/h of speed difference at racing speeds, as here. In real races the breakaway often slows as riders tire, and climbs, wind and team tactics change speeds a lot. Sports directors use similar calculations to time their chase, so the "catch on the line" speed shows the effort needed if the chase wants to wait as long as possible.

Common mistakes

Keep in mind: Steady-speed kinematics only. Real races depend on terrain, wind, drafting and tactics, so treat the result as a guide.

Frequently asked questions

How much time can a chase gain per kilometre?

It depends on the speed difference; 4 km/h at around 45 km/h gives about 7 seconds per km.

Why do breakaways often get caught near the end?

Chasing teams pace the chase to make the catch late, and tired breakaway riders slow down.

What if the chase is slower than the break?

The gap grows and the break will not be caught at steady speeds.

Sources: OpenStax, University Physics Volume 1 (2016), §4.5 "Relative Motion in One and Two Dimensions"

Checked 9 Nov 2026. Constant-speed kinematics and relative velocity (distance = speed × time; closing speed = v_c − v_b), e.g. OpenStax, University Physics Volume 1 (2016), §4.5 “Relative Motion in One and Two Dimensions”.

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